Build determinantes of matrices in cell arrays
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have a cell array X with dimension (N x 2) and N is an even number. This cell array is filled with (2 x 2) Matrices of type double.
I'm wondering, if there is a way to build the determinants of each of those matrices (type: double) in a vectorized manner without using a for loop.
My solution was:
Y = zeros(N,1)
for i = 1:N
Y = det(X{i});
end
Now I have this Y of size (N x 1), which will contain all the determinants of the (2 x 2) matrices stored in the cell array X with size (N x 2).
Can I "vectorize" the for loop in some way or the other?
Thanks for having a look at this!
0 commentaires
Réponse acceptée
KSSV
le 19 Avr 2017
doc cellfun
N = 4 ;
X = cell(N,2) ;
for i = 1:N
X{i,1} = rand(2) ;
X{i,2} = rand(2) ;
end
detX = cellfun(@det,X) ;
5 commentaires
Jan
le 19 Avr 2017
While the cellfun method is nice, it is not "vectorized" actually. You only do not see the loop anymore. Internally you cannot treat the cell elements in a vectorized way.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!