Effacer les filtres
Effacer les filtres

Hough Transform source code explanation

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Ba Ba Black Sheep!
Ba Ba Black Sheep! le 22 Avr 2017
I couldn't understand the following code's for loop.
What is the purpose of the for loop here?
Why is for iterating from 7 to 7?
And, why is num_peak = 3?
clc
close all
clear all
imageCaption = sprintf('scratchedImage.jpg');
inputOriginalImage = imread(imageCaption);
inputOriginalImageGrayscale = rgb2gray(inputOriginalImage);
completelyPreprocessedImage = Preprocessing( inputOriginalImage );
N = 12;
bandpassFilteredImage = BandpassFiltering(completelyPreprocessedImage, N);
[ROWS, COLS, k] = size(bandpassFilteredImage);
homomorphicFilteredImage = HomomorphicFiltering(bandpassFilteredImage, N);
num_peak=3;
length_line=[];
for n=7:7
inputImageForHaughtTransform = bwareaopen( homomorphicFilteredImage(:,:,n),20);
[houghtTransformMatrix, theta, rho] = hough(inputImageForHaughtTransform);
imshow(houghtTransformMatrix,[],'XData',theta,
'YData',rho,'InitialMagnification','fit');
xlabel('\theta'), ylabel('\rho');
axis on, axis normal, hold on;
peaks = houghpeaks(houghtTransformMatrix,3,'threshold',
ceil(0.3*max(houghtTransformMatrix(:))));
x = theta(peaks(:,2));
y = rho(peaks(:,1));
plot(x,y,'s','color','white');
foundLinesInHoughOperation = houghlines(inputImageForHaughtTransform,
theta, rho, peaks,'FillGap',
5,'MinLength',7);
figure, imshow(completelyPreprocessedImage), hold on
MarkLines(foundLinesInHoughOperation, COLS, x, y);
end

Réponse acceptée

Walter Roberson
Walter Roberson le 22 Avr 2017
We do not know. The routines Preprocessing(), BandpassFiltering(), and HomomorphicFiltering() are not Mathworks routines, and they do not appear to be anywhere in a File Exchange contribution either. We do not know what they do.

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