I can not create a matrix

1 vue (au cours des 30 derniers jours)
Muhendisleksi
Muhendisleksi le 26 Avr 2017
Commenté : Stephen23 le 5 Mai 2017
DNdog =
7
11
BNdog =
4
4
blnmynokta =
11
for i = 1:length(DNdog)
for j = 1:(length(blnmynokta))
if (BNdog(i) == blnmynokta(j))
A(i,j) = [1];
elseif (DNdog(i) == blnmynokta(j))
A(i,j) = [-1];
end
end
end
A =
0
-1 % This matrix is formed.
The matrix that should occur is;
  2 commentaires
Jan
Jan le 26 Avr 2017
What exactly is your question?
Muhendisleksi
Muhendisleksi le 26 Avr 2017
A =
0 0 0
0 0 0
0 0 0
-1 0 0
0 -1 0
0 0 -1
I have to get this result. But I could not.

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Stephen23
Stephen23 le 26 Avr 2017
Modifié(e) : Stephen23 le 26 Avr 2017
This is simple with toeplitz:
>> nC = 3;
>> nR = 6;
>> vC = zeros(1,nC);
>> vR = zeros(1,nR);
>> vR(end-nC+1) = -1;
>> toeplitz(vR,vC)
ans =
0 0 0
0 0 0
0 0 0
-1 0 0
0 -1 0
0 0 -1
  3 commentaires
Muhendisleksi
Muhendisleksi le 5 Mai 2017
nC = 6;
nR = 6;
If nC and nR take these values;
A =
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
-1 0 0 1 0 0
0 -1 0 0 1 0
0 0 -1 0 0 1 %How can I get this value?
Stephen23
Stephen23 le 5 Mai 2017
@Muhendisleksi: you can solve this yourself quite easily. One way would be to use zeros and toeplitz and concatenate the outputs on top of each other. When you actually read the documentation and try some examples then you will learn how to use MATLAB and you will learn how to solve problems yourself. Start by reading the docs for the two functions that I told you, and experimenting with them.

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