How to test if a function handle belongs to a particular package?
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    Naor Movshovitz
      
 le 28 Avr 2017
  
    
    
    
    
    Modifié(e) : per isakson
      
      
 le 21 Déc 2017
            I have a method that accepts a function handle and then needs to branch depending on whether that function is part of +package1 or +package2. While I can think of some hacks involving parsing the function name and/or package's help text and/or output of dir, is there a better or simpler way?
thanks, -n
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  Guillaume
      
      
 le 28 Avr 2017
        Probably the simplest would be to parse the output of
functions(yourfunctionhandle)
The file field of that output will contain the full path to the anonymous function, so will contain the package name, if any.
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  Guillaume
      
      
 le 29 Avr 2017
				
      Modifié(e) : per isakson
      
      
 le 21 Déc 2017
  
			Re: documentation. Well, at least it is documented in all versions, so if a change occurs you'll know about it. Saying that, I'm not aware of any major change to the behavior of functions. If you keep with your current design, this is certainly what I'd use.
As Steven says, that design sounds a bit iffy. The way I would implement your requirements would be with functions objects (i.e. classes). I would have an abstract base class from which all functions derive. It is therefore trivial to check whether a function is allowed with isa (or validateattribute) based on its class. To differentiate between the two kind of functions, I would have two additional abstract classes (deriving from the main abstract base class). The whole thing would be something like:
classdef processingfunction 
    methods (Abstract)
        function result = dosomething(this, arg);  %the actual method equivalent to the function handles
    end
end
classdef likelihoodfunction < processingfunction
   %does not need anything extra above the base class. Just a new type
end
classdef lossesfunction < processingfunction
    %does not need anything extra above the base class. Just a new type
end
classdef someactualfunction < likelihoodfunction
    methods
        function result = dosomething(this, arg)
            %actual implementation
            result = arg + 2;
        end
    end
end
function find_best(myset, func)
   validateattributes(fun, {'processingfunction'}, {'scalar'}); %error if func is not derived from processing function
   if isa(func, 'lossesfunction')  %switch behaviour depending of subtype
       result = func.dosomething(1);
   else
       result = func.dosomething(2);
   end
end
There are other advantages to using function objects, such as caching of inputs, precalculating expensive parameters and possibly others. The downside is that OOP in matlab is not always very fast.
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  Image Analyst
      
      
 le 29 Avr 2017
        As an example, to find out the folder of the bwdist function in the Image Processing Toolbox:
functionInfo = which('bwdist')
[folder, baseFileNameNoExt, ext] = fileparts(functionInfo)
Here is the file/folder info that is returned:
functionInfo =
    'C:\Program Files\MATLAB\R2017a\toolbox\images\images\bwdist.m'
folder =
    'C:\Program Files\MATLAB\R2017a\toolbox\images\images'
baseFileNameNoExt =
    'bwdist'
ext =
    '.m'
Adapt as needed for your function names.
5 commentaires
  Image Analyst
      
      
 le 29 Avr 2017
				I got the impression that he "needs to branch depending on whether that function is part of +package1 or +package2" so I figured that if he could figure out the folder where that function lives, then he'd know which package it belonged to. That was my thinking.
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