How do I input this equation into Matlab to show me its graph?

I am having trouble creating a line graph for the following equation: y = rx(1-x/K) - hx/(1+0.05x) where r=0.5, K=100, h=0.8 How can I correctly code this equation into Matlab to show me the graph.

I have used Wolfram to get a general idea of what the graph is supposed to look like, however when I input into Matlab I am getting a hyperbola, which is not right.

function y = example(t, x)

r=0.5;
K=100;
h=0.8;

y = (r.*x.*((1-x)/K)) - ((h.*x)./(1+0.05.*x))

end

In my command window I put in

t=0;
x=[-0.2:0.1:1.2];
example(t,x)
plot(x,y)

[Image Analyst]

You forgot to attach a screenshot from Wolfram of what you think it's supposed to look like. Please do so.

I'm getting what looks like a straight line.

[Darshan Ramakant Bhat]

Also, you are not using the variable 't' anywhere. Please provide the addition details on your question.

[Guillaume]

As already said, t is not used in example so I suspect there is a major error in the code.

As it is, one obvious singularity point is when the denominator is zero, which will obviously happen at x = -20. So plotting the function between -0.2 and 1.2 does not make much sense. Finding the zeros of the cubic polynomial in the numerator would also help.