how to define the below function ?

How to define the function f1= 2n<->2n+1 i.e it defines two transformations.

1. from value 2n to 2n+1.

2.from value 2n+1 to 2n.

Example. i.e let x= 30 (00011110). if we embed 0/1 then the result will be for 0= 30(00011110) i.e 2n for 1= 31(00011111) i.e 2n+1.

Thank you.

Answer 1

[Walter Roberson]

@(v) v + 1 - 2*mod(v, 2)

[aditya sahu]

Dear , Walter Roberson i could not understood your answer, Actually i need to write as function. would you please clarify more in detail about your answer . Thank you.

[Walter Roberson]

function value = f1(x)
  value = x + 1 - 2*mod(x, 2);