Solving simultaneous equations numerically

3 vues (au cours des 30 derniers jours)
diana betancur
diana betancur le 10 Mai 2017
I am unable to get the value of R2 and C, any advice ... thank you
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syms s I1 I2 R2 C
a=8000
a1=4.08E7
l=1;
R=1E6;
e1=(s+R)*I1-R*I2==1;
i1=solve(e1,I1);
e2=-R*i1+(R2+R+1/(C*s))*I2==0;
i2=solve(e2,I2);
v0=(1/(C*s))*i2;
S=solve((1/(R*C+R*R2*C))==a,R/(R*C+R*R2*C)==a1)
  5 commentaires
diana betancur
diana betancur le 11 Mai 2017
yes but I wanted to solve first for C and then plug it into the second equation to get a value for R2
Star Strider
Star Strider le 11 Mai 2017
That won’t work.
Eq1 = (1/(R*C+R*R2*C))==a;
Eq2 = R/(R*C+R*R2*C)==a1;
Eq1 = simplify(Eq1)
Eq2 = simplify(Eq2)
Cs = solve(Eq1, C)
Eq2s = subs(Eq2,C,Cs)
Eq2s = Eq2s * (8000000000*R2 + 8000000000)
R2s = solve(Eq2s,R2)
Eq1 =
8000000000*C*(R2 + 1) == 1
Eq2 =
40800000*C*(R2 + 1) == 1
Cs =
1/(8000000000*R2 + 8000000000)
Eq2s =
(40800000*(R2 + 1))/(8000000000*R2 + 8000000000) == 1
Eq2s =
40800000*R2 + 40800000 == 8000000000*R2 + 8000000000
R2s =
-1

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