Effacer les filtres
Effacer les filtres

how to partially multiply two diffferent dimention matrix

1 vue (au cours des 30 derniers jours)
kavinda hw
kavinda hw le 14 Mai 2017
Commenté : kavinda hw le 16 Mai 2017
A[1,2500] and B[500,1]. how can i multiply 500 form A with B and then Skip 250 positions from A And multiply with B. e.g.., A[1 to 500]*B => store then A[250 to 750] * B=> store ,like wise
  2 commentaires
John D'Errico
John D'Errico le 14 Mai 2017
Interesting. I wonder why two different people are asking the same question?
kavinda hw
kavinda hw le 16 Mai 2017
this is the key technical part of our home work

Connectez-vous pour commenter.

Réponse acceptée

Star Strider
Star Strider le 14 Mai 2017
This works:
A = randi(9, 1, 2500); % Create Data
B = randi(9, 500, 1); % Create Data
for k1 = 1:2
Result{k1} = bsxfun(@times, A(1, (1:500)+(k1-1)*250), B);
end
It produces (500x500) matrices. If you what a different result, I need to know what output you want. It will be easy to change my code to produce it.
  2 commentaires
kavinda hw
kavinda hw le 14 Mai 2017
Modifié(e) : kavinda hw le 14 Mai 2017
Thank you for quick reply but I need 1x1 matrix
Star Strider
Star Strider le 14 Mai 2017
If you want the dot product (or inner product), change the ‘Result’ assignment to:
Result(k1) = A(1, (1:500)+(k1-1)*250) * B;
That will produce your (1x1) scalar result, as desired.

Connectez-vous pour commenter.

Plus de réponses (1)

Michael Saniuk
Michael Saniuk le 14 Mai 2017
>> A = rand(1250,1);
>> B = rand(1,500);
>> C = A(1:500,1).*B';
>> D = A(251:750,1).*B';

Catégories

En savoir plus sur Multidimensional Arrays dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by