How to generate random integers from the uniform distribution between two numbers

Assume matrix A as follows:

A = [
810  840
840  870
870  900
900  930
930  960
];

For every row in matrix A,I want to generate random integers from the uniform distribution between column 1 and column 2. Also, these random numbers should be divided by 5 with decimal 0 (e.g. 810 (not 811)).

The output matrix size should be 5*1.

I think the right function is randi, but I don't know how to form it.

[the cyclist]

Are the entries in A always multiples of 5?

Do you want to the numbers strictly between? For example, in the first row, do you want 810 and 840 included or excluded?

[Zhan]

Thank @the cyclist.

Yes, the entire in A always multiples of 10. For the second part of your question, also, Yes. For example for the first row, 810 and/or 40 can be included. Thanks!

[Stephen23]

@Zhan: you keep asking questions, but you have not accepted any of the answers to any of your questions. Accepting answers shows which answer solved your question, and is also an easy way for you to say "thank you" for our volunteer effort helping you.

Answer 1

[the cyclist]

Under the assumption that you want to include the endpoints, and that the elements of A are evenly divisible by 5:

A = [
810  840
840  870
870  900
900  930
930  960
];

nrows = size(A,1);

r = zeros(nrows,1);
for nr = 1:nrows
    r(nr) = 5*randi(A(nr,:)/5);
end

Answer 2

[Guillaume]

Simply loop over the rows:

result = zeros(size(A, 1), 1);
for row = 1:size(A, 1)
   result(row) = randi(A(row));
end

I do not understand "these random numbers should be divided by 5 with decimal 0"

[the cyclist]

I believe he wants the output results to be only numbers that are evenly divisible by 5.

[Zhan]

Yes, you are right.

[Guillaume]

Oh! Well, in that case, simply divide the bounds by 5 and multiply the integer results by 5 afterward.