How do you use the else if commands to alter variables in matrices?

The question below is directly the question i am having extreme difficuilty with. I have no idea how to use elese if commands to do this question, thats why it is hard ,. If it was just subtracying values from a table then it would be easy to do but it saids to use eleseif commands. So yeah . Good luck

Create a two dimensional array (matrix) of dimension 5 X 5 of zeros, using the zeros(r,c)
command. Next overwrite some of the zeros to reproduce the matrix shown below. Do this
by using nested loops and a if...elseif...else...end statement to assign the dierent
values to the table of numbers. When you have initialized the array elements print out your
matrix to check, it should look like the one below.

0 0 0 5 8

0 0 5 8 3

0 5 8 3 0

5 8 3 0 0  

8 3 0 0 0

[Rahul]

This looks like a homework question..

Answer 1

[Kye Taylor]

It helps to realize that the sum of the indices is constant along anti-diagonals in a matrix (while the difference is constant along diagonals)... Therefore, how about

 m = 5;
 n = 5;
 A = zeros(m,n);

 for i = 1:m
     for j = max(1,n-i):min(n,n+2-i)
         if (i+j == 5)
             A(i,j) = 5;
         elseif (i+j == 6)
             A(i,j) = 8;
         else
             A(i,j) = 3;
         end
     end
 end

 disp(A)

Answer 2

[Andrei Bobrov]

n = 5
M = full(spdiags(ones(n,1)*[3 8 5],[-1 0 1],n,n))
out = M(:,end:-1:1)

OR

M = zeros(n)
M([n-1:n-1:n^2-2*n+1;2*n:n-1:n^2-1]) = [5; 3]*ones(1,n-1)
M(n:n-1:n^2-1) = 8