Trying to go from 1 matrix to a structure with a condition in the next column

Hello, so I have a [1x996] matrix that I am trying to break up to read two different outcomes: for all values less than 1.5, the values are considered critical for all values greater than 1.5, the values are considered not critical Ideally, I want to make a struct with the first column stating the values in the 1x996 matrix and the second column stating if the number from the first column is critical or not critical.

I have tried a variety of for loops and if else statements, but I can't get the values to list them all together in the correct order (if I pull out all of the criticals and all of the not criticals, then they will not be in the right line position for matlab for my other files of code. The picture illustrates what I am trying to do.

This is where I am at:

if true
  % for i=1:length(LabeledSituations)
  All_CutIn = (strcmp(LabeledSituations(i).CutIn_Label,'CutIn'));
  CutIn_files = find(All_CutIn == 1);
  dx = LabeledSituations(i).Data.Signals(114).Value;
  dvx = LabeledSituations(i).Data.Signals(116).Value;
  TTC = dx./dvx; 
  real_TTC = TTC(CutIn_files)  
%%% i need to make a structure where the first column is the numerical
%%% values and the second column is the condition (critical or nc) 
   critical_TTC = real_TTC(real_TTC < 1.5);
   nc_TTC = real_TTC(real_TTC > 1.5);
end
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Answer 1

[Matt J]

I want to make a struct with the first column stating the values in the 1x996 matrix and the second column stating if the number from the first column is critical or not critical.

I can't tell what you mean by "struct". It sounds like what you really want is a 2x966 matrix,

result=[A(:), A(:)<1.5];

[MIRANDA WHAH]

this actually works perfectly! now I have a table of two columns, the first being the values and the second being the condition. however instead of the second column reading zero and ones, is there a way for me to change it to read 'not critical' or 'critical'? i can#t figure out how to do this in a matrix.

also, a struct is just structure. it is similar to a table but allows to link to more sets of data

[Matt J]

Not sure why Andrei's approach didn't work, but here's an analogous one with cell arrays

A=0:5;  %example

t=A(:)<1.5;
s={'critical';'non-critical'};

result=[num2cell(A(:)), s(t+1)]

will give

result =

6×2 cell array

    [0]    'non-critical'
    [1]    'non-critical'
    [2]    'critical'    
    [3]    'critical'    
    [4]    'critical'    
    [5]    'critical'

Answer 2

[Andrei Bobrov]

t = real_TTC >= 1.5;
s = {'critical';'non_critical'};
T = table(real_TTC,s(t + 1),'VariableNames',{'A' 'critical'});

[MIRANDA WHAH]

This makes sense! however there is an error

 Error using table (line 253)
All variables must have the same number of rows.
 Error in SafetyAnalysis (line 66)
T = table(real_TTC,s(t + 1),'VariableNames',{'A' 'critical'});

I am wondering if there is a way to go around this, because there wont be the same number of critical and not critical values. Also, could you explain to me why you used "s(t+1)" ?

[Guillaume]

You would get an error if real_TTC is a row vector. To fix:

T = table(real_TTC(:), s(t + 1), 'VariableNames', {'A' 'critical'});

The t+1 is to convert logicals (0/1) into valid matrix indices (1/2).

I would recommend you use a categorical array instead of acell array of chars for your second column:

T = table(real_TTC(:), ...
          categorical(real_TTC(:), [false, true], {'critical', 'non_critical'}), ...
          'VariableNames', {'agoodname', 'criticality'})

[Andrei Bobrov]

Small typo. I'm fixed:

T = table(real_TTC(:), ...
          categorical(real_TTC(:) >= 1.5, [false, true], {'critical', 'non_critical'}), ...
          'VariableNames', {'agoodname', 'criticality'})

Thank you Guillaume!