Writing Video Frames in Parallel
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So I came up with a way to write video frames in parallel so that I could take advantage of all the cores in my computer only I keep getting a weird bug where I can only write videos up to 52.1 MB. Does anyone have any idea what might be going on? Below is my code I've been using to write video frames in parallel.
spmd(1,4)
open(videoWriter);
CountIndex = [0];
for i = labindex:numlabs:numFiles
if labindex == 1
frame1 = imread(fullfile(workingDirectory, stackName, imageFiles(i).name));
end
if labindex == 2
frame2 = imread(fullfile(workingDirectory, stackName, imageFiles(i).name));
end
if labindex == 3
frame3 = imread(fullfile(workingDirectory, stackName, imageFiles(i).name));
end
if labindex == 4
frame4 = imread(fullfile(workingDirectory, stackName, imageFiles(i).name));
end
while ~any(abs(CountIndex-(labindex-1))<1e-10)
end
if labindex == 1
writeVideo(videoWriter,frame1);
end
if labindex == 2
writeVideo(videoWriter,frame2);
end
if labindex == 3
writeVideo(videoWriter,frame3);
end
if labindex == 4
writeVideo(videoWriter,frame4);
end
CountIndex = [CountIndex labindex];
if length(CountIndex) == length(numlabs)+1
CountIndex = [0];
end
end
end
end
6 commentaires
Walter Roberson
le 29 Mai 2017
That
while ~any(abs(CountIndex-(labindex-1))<1e-10)
end
is a nasty hack. Have you considered using one of the labs to write the data, with the others using labSend to send what they have read?
Jacob Mevorach
le 29 Mai 2017
Walter Roberson
le 29 Mai 2017
spmd
if labindex == numlabs
open(videoWriter);
for i = 1 : numFiles
frame = labReceive( 1 + mod(i - 1, numlabs-1) );
writeVideo(videoWriter, frame);
end
else
for i = labindex:numlabs-1:numFiles
frame = imread( imageFiles(i).name );
labSend(frame, numlabs);
end
end
end
Jacob Mevorach
le 30 Mai 2017
Modifié(e) : Jacob Mevorach
le 30 Mai 2017
Walter Roberson
le 30 Mai 2017
You should not need that extra labSend / labReceive: the labReceive specifies which worker it is waiting to hear from and it cycles through the workers, so if (say) worker 3 has the data ready before worker #2, then the data from worker 3 will sit in the queue until the labReceive(3) is executed. If worker 3's data is not ready yet then labReceive(3) would wait for it.
The one thing I do not know, though, is what happens if you cue multiple items, whether a single labReceive will pick them all up.
Here is another way to avoid the labSend / labReceive that you added:
spmd
if labindex == numlabs
open(videoWriter);
for i = 1 : numFiles
frame = labReceive('any', i);
writeVideo(videoWriter, frame);
end
else
for i = labindex:numlabs-1:numFiles
frame = imread( imageFiles(i).name );
labSend(frame, numlabs, i);
end
end
end
p = parpool();
f(1:numFiles) = parallel.FevalFuture;
for i = 1 : numFiles
f(i) = parfeval(p, @imread, 1, imageFiles(i).name );
end
open(videoWriter);
for i = 1 : numFiles
frame = fetchOutputs(f(i));
writeVideo(frame);
end
delete(f);
Jacob Mevorach
le 30 Mai 2017
Modifié(e) : Jacob Mevorach
le 30 Mai 2017
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