How do you fill a structure with a large amount of values? For example, I've preallocated my structure as:
met.position = cell(400, 1);
I'd like all 400 rows to equal 'string' or some character value. I could fill it with a loop but is there a shorter/easier way?
Thanks!

 Réponse acceptée

Jan
Jan le 2 Avr 2012

1 vote

met.position = cell(400, 1);
met.position(:) = {'default'};
Or:
met.position = repmat({'default'}, 400, 1);

1 commentaire

Trader
Trader le 2 Avr 2012
You're the man Jan, thank you!

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