Info

Cette question est clôturée. Rouvrir pour modifier ou répondre.

how to simulate a function

1 vue (au cours des 30 derniers jours)
Fatma Abdullah
Fatma Abdullah le 31 Mai 2017
Clôturé : Stephen23 le 31 Mai 2017
i'm trying to simulate this function "pd" against "lnd" by accept reject monte carlo method but it takes forever and nothing comes out
M=8;
N=32;
K=14;
c=2;
s=1;
T=18.623390280430364437245197384232;
lnd=0:5:30;
pd1=(2*K*nchoosek(N/2,K)*((gamma(K+i)*gamma(N-K+i+1+T./(1+lnd)))./(gamma(N+1+T./(1+lnd)))-...
(symsum(nchoosek(N/2,i)*(gamma(K+i)*gamma(N-K-i+1+T./(1+lnd)))./(gamma(N+1+T./(1+lnd))), i, K, (N/2)))));
%lnd=0:5:30;
pd=(symsum(nchoosek(M,i)*(pd1).^(i).* (1-(pd1)).^(M-i), i, s, M));
O=10^7;
Mx=1.2*max(pd);
lndi=10*rand(1,O);
pj=10*rand(1,O);
pd1i=2*K*nchoosek(N/2,K)*((gamma(K+i)*gamma(N-K+i+1+T./(1+lndi)))./(gamma(N+1+T./(1+lndi)))-...
(symsum(nchoosek(N/2,i)*(gamma(K+i)*gamma(N-K-i+1+T./(1+lndi)))./(gamma(N+1+T./(1+lndi))), i, K, (N/2))));
f_lndi=(symsum(nchoosek(M,i)*(pd1i).^(i)* (1-(pd1i)).^(M-i), i, s, M));
comp=pj*Mx;
result=f_lndi>=comp;
index=find(result);
lnd_new=lndi(1,index);
[pd1,lnd1]=hist(lnd_new,100);
dlnd=(lnd1(2)-lnd1(1));
h=(pd1/length(lnd_new))/dlnd;
plot(lnd1,h,'b.');

Réponses (1)

Walter Roberson
Walter Roberson le 31 Mai 2017
As I told you in https://www.mathworks.com/matlabcentral/answers/342612-why-does-it-take-forever-to-solve-a-function, do not use symsum() for adding definite symbolic terms.

Cette question est clôturée.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by