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Interpolating a function that is constant over some parts of its domain?

5 vues (au cours des 30 derniers jours)
I'm trying to write code that will linearly interpolate samples from a generic real-valued function. Interp1 seems to break if the function is constant over any part of its domain, and unfortunately for me this is an extremely common use case - as a simple function:
{0, if x<0
f(x) = {x, if 0<=x<=1
{1, otherwise
It seems like interp1([0, 0, 1, 1], [-10,0,1,10], x) ought to return this function (for x \in [-10,10]), but instead I get the error that "The grid vectors must contain unique points."
Is there another interpolation function that doesn't break when you feed it functions that are sometimes constant?
  1 commentaire
Stephen23
Stephen23 le 12 Juin 2017
The interp1 help page shows the syntax:
vq = interp1(x,v,xq)
where x is the independent variable. You have the x and v swapped around.

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David Goodmanson
David Goodmanson le 12 Juin 2017
Modifié(e) : David Goodmanson le 12 Juin 2017
Hi Jonathan,
just swap inputs,
interp1([-10,0,1,10], [0,0,1,1], x)

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