remove row with matching string

5 vues (au cours des 30 derniers jours)
Trader
Trader le 5 Avr 2012
I'm trying to eliminate an entire row of data if a string is found in the cell array.
Sample array values:
myarray =
[ 16] '10/05/2011' '11:20' 'waiting' 'nopos' [ 10000]
[ 17] '10/05/2011' '11:25' 'open' 'long' [ 0]
[ 34] '10/05/2011' '12:50' 'open' 'short' [ 0]
so i'd like to have:
my array =
[ 17] '10/05/2011' '11:25' 'open' 'long' [ 0]
[ 34] '10/05/2011' '12:50' 'open' 'short' [ 0]
there can be several occurances in the array, I'm not looking to pop the top row...
you help is greatly appreciated
  1 commentaire
Image Analyst
Image Analyst le 5 Avr 2012
So which element in the cell array are you checking for the string? In column 4 or column 5, or something else.

Connectez-vous pour commenter.

Réponses (2)

Jan
Jan le 5 Avr 2012
array(strcmp(array(:, 4), 'waiting'), :) = [];

Richard Brown
Richard Brown le 5 Avr 2012
If it can occur anywhere, use cellfun to test for equality:
[I, ~] = find(cellfun(@(s) isequal(s, 'waiting'), myarray));
myarray(I, :) = [];
otherwise, you can pull out the column of interest and use ismember
I = ismember(myarray(:, 4), 'waiting')
myarray(I, :) = [];
  4 commentaires
Richard Brown
Richard Brown le 5 Avr 2012
And yes, just checked - for a cell array vector of 100000 strings, on my computer strcmp takes 0.01 seconds, whereas ismember takes 0.03 :)
Jan
Jan le 5 Avr 2012
0.02 seconds lost. But if you do this 10e6 times... :-)
I've overseen, that your FIND command operates on a matrix. Then the 2nd omitted output does matter, as you have written.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Operators and Elementary Operations dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by