Replace data inside a loop.

    for N=10:10
        count2=count2+1;  
    for ii=1:last 
        a=abs(rand(1,N)) 
    for n =1:N

count=0;
for angle=0:360
   count=count+1;

Xd=(D*cos(angle*pi/180));
Yd=(D*sin(angle*pi/180));
d1(n,count)= sqrt((Yd-y(n))^2+(Xd-x(n))^2);%distance between destination and sensor for 0 to 360 degree.
k(n,count)=((2*pi)/lambda)*(d1(n,count)); %phase lag for each sensor.
yy(n,count)=(exp(-i*k(n,count))*c(n)*a(n)); %weight multiplication to correct the phase lag.

end
Y=sum(yy);
YY=abs(Y);
p=20*log10(YY/max(YY));%normalized power in dB.

end
end
end

I want to replace the (a) value for each loop of (for ii=1:last) loop. i want to replace the new (a) value with the old (a) value. how can I do that?

[Jan]

RAND replies non-negative values only. Therefore ABS() is not required.

Answer 1

[Jan]

Please explain how the first a value is defined, if you replace each a by the former value.

Usually such problems are solved like this:

aOld = 0;
for i = 1:100
  a = rand;
  % Your computations here, e.g.:
  disp(a - aOld);
  ...
  aOld = a;
end

[Kugen Raj]

the first a value is calculated using (a=abs(rand(1,N))). then for each ii loop, new a value will be calculated.

[Jan]

Again: The ABS() is not required here.

Does this mean, that your problem is solved?

[Kugen Raj]

well, that is because i want the a value to be a positive value. If i don't use abs(), i would get a negative value too.