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seperate elements in cell array

3 vues (au cours des 30 derniers jours)
Mate 2u
Mate 2u le 5 Avr 2012
Hi everybody I have a massive cell array in the form of:
'GLD|41|R|10|05:28:06:361|01/08/2011|f98=158.6'
'GLD|41|T|10|05:28:06:361|01/08/2011|f2=158.3659'
'SLV|41|R|10|05:28:18:901|01/08/2011|f98=39.1628'
'SLV|41|T|10|05:28:18:901|01/08/2011|f2=38.8504'
'GLD|41|R|10|05:28:21:755|01/08/2011|f98=158.6'
'GLD|41|T|10|05:28:21:755|01/08/2011|f2=158.3659'
'SLV|41|R|10|05:28:34:285|01/08/2011|f98=39.1628'
It is always SLV or GLD.
How can I separate this cell array into two cell arrays where one is for all the SLV entries and one is for the GLD entries?
Thanks

Réponse acceptée

Wayne King
Wayne King le 5 Avr 2012
I'm assuming each string above is one element of the cell array. To find the SLV and put them in a cell array.
X = {'GLD|41|R|10|05:28:06:361|01/08/2011|f98=158.6',...
'GLD|41|T|10|05:28:06:361|01/08/2011|f2=158.3659',...
'SLV|41|R|10|05:28:18:901|01/08/2011|f98=39.1628',...
'SLV|41|T|10|05:28:18:901|01/08/2011|f2=38.8504',...
'GLD|41|R|10|05:28:21:755|01/08/2011|f98=158.6',...
'GLD|41|T|10|05:28:21:755|01/08/2011|f2=158.3659',...
'SLV|41|R|10|05:28:34:285|01/08/2011|f98=39.1628'};
Y = cellfun(@(x)x(1:3),X,'UniformOutput',false);
Y1 = strcmp(Y,'SLV');
X1 = X(Y1>0);
Then X1 contains only the 'SLV' entries. You can do the same for 'GLD'.
  1 commentaire
Mate 2u
Mate 2u le 6 Avr 2012
Great work.

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