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How to modify number of characters for numeric values in a cell array?

3 vues (au cours des 30 derniers jours)
Calabrese
Calabrese le 15 Juil 2017
Modifié(e) : Calabrese le 15 Juil 2017
Within a cell array, I would like to limit the number of characters allowed in each cell to 6. If the cell has more than 6 characters, I would like to remove the characters off of the end. i.e.
n_raw =
[ 0.023391]
[ 0.31236]
[ 0.0073958]
[ 0.6252]
[ 14.158]
[ 14.159]
[ 0.046701]
[ 0.095463]
to
n_raw =
[ 0.0233]
[ 0.3123]
[ 0.0073]
[ 0.6252]
[ 14.158]
[ 14.159]
[ 0.0467]
[ 0.0954]
  5 commentaires
Calabrese
Calabrese le 15 Juil 2017
Could I convert them to characters, reduce them, and then convert them back to numbers?
per isakson
per isakson le 15 Juil 2017
Why not try?
You have to distinguish between internal representation and what's displayed.
>> cac{1} = 1/3;
cac{2} = 33.3;
cac
cac =
[0.3333] [33.3000]
>> format long
>> cac
cac =
[0.333333333333333] [33.299999999999997]

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Réponse acceptée

Walter Roberson
Walter Roberson le 15 Juil 2017
Under the assumption that each entry in the cell is a column vector, and cell itself is a column vector, but not assuming that each entry is a scalar:
n_raw = {
0.023391
0.31236
0.0073958
0.6252
14.158
-14.159
0.046701
0.095463 };
rv = vertcat(n_raw{:});
new_n_raw = mat2cell( floor(abs(rv) * 10000) / 10000 .* sign(rv), cellfun(@length, n_raw), 1);
Note, however, that the only fractions that can be represented exactly in 4 decimal digits are the integer multiples of 1/16 (e.g., 5/16 or 6/16 = 3/8 can be represented exactly in 4 decimal digits, but 11/32 cannot be represented exactly in 4 decimal digits.) In all other cases, the rounding to 4 decimal digits will only look to work. For example, what looks like 0.023391 rounded to what looks like 0.0233 would actually become 0.02330000000000000126565424807267845608294010162353515625

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