Creating variables consisting of many elements

I want to create a variable consisting of X1 to X10 . Is there an easy way instead of typing X1 to X10?

V1={'X1','X2','X3','X4','X5','X6','X7','X8','X9','X10'}

Thanks

[the cyclist]

Your problem is upstream, and is a great illustration of why it is almost always a terrible idea to name variables X1, X2, etc.

Can you fix that prior code, to use a vector with elements X(1), X(2), or a cell array with elements X{1}, X{2}, etc?

If that is impossible, there are still solutions to your awkward problem, via even more awkward methods. What is the class and size of X1, etc?

[Stephen23]

@Gratitude Kim: what do you need these string for? The best solution may well depend on your usecase.

>> arrayfun(@(n)sprintf('X%d',n),1:10,'uni',0)
ans =
  'X1'
  'X2'
  'X3'
  'X4'
  'X5'
  'X6'
  'X7'
  'X8'
  'X9'
  'X10'

or perhaps

>> regexp(sprintf('X%d ',1:10),'\S+','match')

If you are planning on accessing variables with those names then DON'T. Read this to know why:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

[Gratitude Kim]

Thanks for your assistance.

Answer 1

[Daniel Burke]

From your question it looks like you want V1 to be a cell array of strings, ranging from 'X1' to 'X10', this code should do the trick if that is your goal:

 V1 = cell(1,10)
 for i = 1:10
     V1{i} = ['X' num2str(i)]
 end

Answer 2

[Jan]

Or the undocumented function sprintfc:

sprintfc('X%d', 1:10)

[Andrei Bobrov]

+1

Answer 3

[Philip Borghesani]

If you don't mind strings and have R2017a I like:

 "x"+(1:10)

Or if you want a cell array or have 2016b:

 cellstr(string('x')+(1:10))

[Andrei Bobrov]

+1