How to calculate maximum up to current point?

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Steven Niggebrugge
Steven Niggebrugge le 18 Août 2017
Commenté : John D'Errico le 18 Août 2017
Hi, how can i calculate the an array of current maxima, i.e. for each point in the array to calculate the maximum from the first observation of the array to the current? e.g. for array [3 8 10 6] i want the output to be [3 8 10 6] ?
Is there a function to do this (movmax i think it works for a fixed lookback or lookforward) or do i just need to loop through all observations?
  2 commentaires
José-Luis
José-Luis le 18 Août 2017
You probably meant [3,8,10,10] as your result.
Steven Niggebrugge
Steven Niggebrugge le 18 Août 2017
yes indeed, thanks very much!

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Réponses (2)

John D'Errico
John D'Errico le 18 Août 2017
cummax([3 8 10 6])
ans =
3 8 10 10
  2 commentaires
José-Luis
José-Luis le 18 Août 2017
Modifié(e) : José-Luis le 18 Août 2017
+1
Whenever I think of a tortured way, there's a built-in function. It is hard to keep up.
John D'Errico
John D'Errico le 18 Août 2017
I keep learning new things on Answers. New little goodies that appeared when I was not watching. I guess we all should read the release notes religiously. That would take all the fun out of it though. :)

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José-Luis
José-Luis le 18 Août 2017
a = [3,8,10,6,5,11,12,-20];
n = numel(a);
result = tril(bsxfun(@minus,a,a'));
[~,idx] = max(result,[],2);
result = a(idx)

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