Iteration Without the Implementation of Loops

I am interested in being able to run this particular code using i as the iterating vector. While this can easily be accomplished using a for-loop, I would like to do this without using loops of any kind. Essentially what I want is for the vector q to contain all ten values of F when q is solved for a given i-value. The issue currently is that F does not take any value of i, so I am left with an empty x-matrix in the end. I want to iterate for each value of i in the vector, but without using loops. Does anybody have any suggestions?

   %%%Test program

%%Clear variables

close all; 
clear all;
clc;

%%Definitions

syms q

x = [];

i = 1:10;

F = i - 2*q == 0;

solq = solve(F,q);

x = (x,solq)

[BM]

I tried to adapt this base program to my needs, but I am running into an issue. In my particular program I have my function F dependent on other functions. Would you have suggestions on how to incorporate the same idea if the program was modified to include

q = sym('q',[1,10]);
i = 1:10;
M = @(q) tan(q)/(1+sin(7*q))
N = log(M(q))
F = i - 2*q*N == 0;
solq = solve(F,q)

I obtain the same errors in this program that I do in my actual program, and would appreciate understanding a little more why this is the case. If I solved F via for-loops, everything works. Thanks for your time.

Answer 1

[John D'Errico]

q = sym('q',[1,10]);
i = 1:10;
F = i - 2*q == 0;
solq = solve(F,q)
solq = 
  struct with fields:

       q1: [1×1 sym]
       q2: [1×1 sym]
       q3: [1×1 sym]
       q4: [1×1 sym]
       q5: [1×1 sym]
       q6: [1×1 sym]
       q7: [1×1 sym]
       q8: [1×1 sym]
       q9: [1×1 sym]
      q10: [1×1 sym]

solq.q3
ans =
3/2

I suppose you could use an implicit loop too, in the form of cellfun. But the above works.

[BM]

The code above does not seem to work. It breaks down at the 'solq = struct with fields' command. Could I ask how I would use the alternative form you suggested as well to accomplish this feat? I was always under the impression I was going to have to use some kind of matrix multiplication to get this to work.

[Adam]

That's not a command, that's just the output from the previous command, in the command window.

[BM]

Yeah, I realized that after when I arrived at the chapter (in a reference book) that dealt with such information. Sorry for my confusion. Thanks again!