Add matrix to matrix
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Let's say: A=zeros(7,2):
A=[ 0 0
0 0
0 0
0 0
0 0
0 0
0 0]
B=[4 1 3] ; C=[1 1 1] ;
D=[2 5 7 6]; E=[2 2 2 2]
How can I add two matrix B,C,D,E to matrix A to get the result as follows:
F=[ 4 1 ......add B, C.......
1 1 ......add B, C.......
3 1 ......add B, C.......
2 2 ......add D, E.......
5 2 ......add D, E......
7 2 ......add D, E......
6 2] ......add D, E......
In general, let's say :
A=zeros(1000,2)
B1=[1; 2; 3;....100] ; index_B1= [1;1;1;.....1] {100 element 1}
B2=[101;102;103....300]; index_B2= [2;2;2;.....2] {200 element 2}
B3=[301;302;303....600]; index_B3= [3;3;3;.....3] {300 element 3}
..................................................................
B7=[801;802;803....850]; index_B7= [7;7;7;.....7] {50 element 7}
...................................................................
Bi=[921;922;923....1000]; index_Bi=[i;i;i;.....i] {80 element i}
1/ How to create matrix index_Bi according to the number of element in matrix Bi? (If possible please use while or for ...loop to do)
2/ After that, How to add two matrices (Bi & index_Bi) to matrix A, we will have the result:
F=[ B1 index_B1
B2 index_B2
B3 index_B3
..............
B7 index_B7
.............
Bi index_Bi]
1 commentaire
Réponse acceptée
Andrei Bobrov
le 30 Août 2017
Modifié(e) : Andrei Bobrov
le 30 Août 2017
B = {B1;B2;B3;B4...;Bi}; % Please create B array.
n = cellfun(@numel,B);
A = [cell2mat(B),repelem((1:numel(n))',n)];
5 commentaires
Guillaume
le 31 Août 2017
You should never have matrix B1, B2, ... Bn in your workspace. As soon as you start numbering matrices, you should stop and change the way you work. These numbered matrices are obviously relatedm they should therefore be stored together into a single container variable such as the cell array that Andrei used.
Plus de réponses (2)
KL
le 30 Août 2017
N = [B.' C.';
D.' E.'];
F = A+N
Why E has only 3 elements? I'd assume you missed out something there.
1 commentaire
Guillaume
le 30 Août 2017
In your particular example, and assuming that E is supposed to have 4 elements instead of the 3 you've written:
F = A + [B.', C.'; D.', E.']
I have no idea where you're going with this question, so can't answer in a generic way.
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