Error encountered for numerical integration inside for loop.

16 vues (au cours des 30 derniers jours)
Jay
Jay le 12 Sep 2017
So this is the code I'm trying to run -
q=10e8:10000:20e9;
s=length(q);
epso = 8.8 *10.^-12;
epsr=5.7;
ro=3.63*(10.^-3);
epsl = 2.5;
ri=1.13*(10.^-3);
copen = (epso/sqrt(epsr)*log(ro/ri));
cload= (epsl/sqrt(epsr)*log(ro/ri));
t = zeros(1,s);
for f = 1:length(q)
fun = @(x)(((((besselj(0,(2*pi*q(f))/(3e8))*x*ro)-besselj(0,(2*pi*q(f))/(3e8))*x*ri)).^2)./x).*freload(x,q)));
y(f) = copen*abs(integral(fun,0,Inf));
t(f)=(1-y(f))/(1+y(f));
end
plot (q,t);
where the function freload is
function f = freload(x,q)
epsl=3.4;
f=(1./sqrt(epsl-(x.^2))).*(1+exp(-2*1i*2*pi*q./(3e8).*sqrt(epsl-(x.^2))))./((1-exp(-2*1i*2*pi*q/(3e8).*sqrt(epsl-(x.^2)))));
end
The errors I get are as follows -
Error using integralCalc/finalInputChecks (line 515)
Output of the function must be the same size as the input. If FUN is an array-valued integrand, set the
'ArrayValued' option to true.
Error in integralCalc/iterateScalarValued (line 315)
finalInputChecks(x,fx);
Error in integralCalc/vadapt (line 132)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 83)
[q,errbnd] = vadapt(@AToInfInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in numint (line 14)
y(f) = copen*abs(integral(fun,0,Inf));
The program seems to be giving an output for other functions. Any help would be appreciated greatly.

Réponse acceptée

Walter Roberson
Walter Roberson le 12 Sep 2017
Your line
fun = @(x)(((((besselj(0,(2*pi*q(f))/(3e8))*x*ro)-besselj(0,(2*pi*q(f))/(3e8))*x*ri)).^2)./x).*freload(x,q)));
calls freload() passing in all of q, instead of q(f)

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