E(z)=(lamb​da*z*R)/(2​*E_initial​*((z.^2+R^​2)^(3/2)))

Réponses (1)

Walter Roberson
Walter Roberson le 16 Sep 2017
E = (lambda .* z .* R) ./ (2 .* E_initial .* ((z.^2 + R.^2).^(3/2)))

2 commentaires

Maria V Alberico
Maria V Alberico le 17 Sep 2017
Thank you but it's still not working.
What are the values for your variables? What result are you getting? What result do you expect to see?
Perhaps you need
E = @(z) (lambda .* z .* R) ./ (2 .* E_initial .* ((z.^2 + R.^2).^(3/2)))
if you are trying to create a function

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