Vectorised cell search and logical indexing

Hello, I would like to know if there is a vectorised/cellfun/better approach to the loop below:
% Find Key 4 in block_new{:}(1,1)
Key4 = '=x';
index4 = cellfun(@(x)regexp(x, Key4), block_new, 'UniformOutput', false);
Logic = false(length(index4),1);
for i = 1 : length(index4)
Logic(i) = ~isempty(cell2mat(index4{i}(1,1)));
end
index4 = Logic;
block_set = block_new(:,index4);
Where the cells in the 1 X m cell array, block_new are in themselves cell arrays of various sizes.
I have already tried the following:
find(~cellfun(@isempty,index4{:}(1,1)))
Thanks in advance.

3 commentaires

Jos (10584)
Jos (10584) le 21 Sep 2017
what does block_new contain? Is it a cell array of strings?
Yes. A typical example, let's say block_new{i} would contain:
block_new{i}(1,1) -> String
block_new{i}(1,2:n} -> String of comma delimited doubles
~isempty(cell2mat(index4{i}(1,1)));
If the output of cell2mat is empty, the cell must have been empty already. What about:
~isempty(index4{i}{1})
instead?
Please post a relevant input array.

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Réponses (1)

Jos (10584)
Jos (10584) le 21 Sep 2017
regex can work on a cell array of strings directly:
block_new = {'abcd=x','abcd','a=xbc=x'}
index4 = regexp('block_new','=x')

3 commentaires

Apparently they are not all strings..
regexp(block_new,'=x')
Error using regexp
All cells must be char row vectors.
Jos (10584)
Jos (10584) le 21 Sep 2017
Some cells are cell array of strings themselves? Kind of complicated data structure ...
Cedric
Cedric le 21 Sep 2017
Modifié(e) : Cedric le 21 Sep 2017
As mentioned by Jan, it would be simpler if you would attach a sample data set. Also, if you could describe in words what you are trying to achieve, that could help because you are doing a lot of operations that seem unnecessary (but that may in fact be necessary depending the final purpose).

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Question posée :

le 21 Sep 2017

Modifié(e) :

le 21 Sep 2017

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