Calculate the remaining index of my data
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
muhammad ismat
le 27 Sep 2017
Commenté : muhammad ismat
le 28 Sep 2017
If i have
x= 1 2
3 4
2 5
1 5
is the index of my data. i want to get on remaining of these index but not need index that have i=j i.e [ (1 1) (2 2) (3 3)(4 4)(5 5) and not need fliplr of x i.e [(2 1)(4 3)(5 2)(5 1)]. so i want to the result
result=
1 3
1 4
2 3
2 4
3 5
4 5
that should not contain fliplr of any index.
1 commentaire
Rik
le 27 Sep 2017
It is not clear what your question is. It sounds like you could solve your problem with logical indexing, or even find (and maybe a call to ismember(fliplr(A),A)), but without understanding your problem better I can't help you with actual code.
Réponse acceptée
the cyclist
le 27 Sep 2017
Here is one way.
x= [1 2
3 4
2 5
1 5];
result = zeros(5*2,2);
ri = 1;
for ii=1:5
for jj = ii+1:5
result(ri,:) = [ii jj];
ri = ri+1;
end
end
isRowToRemove = ismember(result,x,'rows');
result(isRowToRemove,:) = [];
There is certainly a better way to pre-populate the array result with all possible row values than using the loops, but I got lazy.
Plus de réponses (1)
OCDER
le 27 Sep 2017
%Getting index of an arbitrary matrix
[x, y] = find(ones(5, 'logical'));
x = [x y];
%Remove index i == j
x(x(:,1) == x(:,2), :) = [];
%Get unique x,y and not those that are y,x
x = unique(sort(x, 2), 'rows');
x =
1 2
1 3
1 4
1 5
2 3
2 4
2 5
3 4
3 5
4 5
0 commentaires
Voir également
Catégories
En savoir plus sur Structures dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!