Simulink Integrator

3 vues (au cours des 30 derniers jours)
Daniel W
Daniel W le 19 Avr 2012
Looking to go back to complete basics on how some aspects of Simulink work and am running into something mathematically that seems off. I've made a simple program with blocks (sine wave)->(1/s)->(Scope) with an additional scope set up to view the initial sine wave. I've set the amplitude of the sin wave to 1 and run the program. The sine wave plot looks correct, ±1 amplitude and the wave starts at (0,0), like a normal sine wave. The integral of a sine wave is -cos, so I expect to see a wave that runs ±1 and starts at (0,1), but what simulink outputs is a sine wave that starts at (0,0) and the amplitude runs from 0 - 2, not ±1. Am I missing something on how to set up a signal to be integrated? If I use the derivative function, I do get a cos wave. Any thoughts?

Réponses (1)

Titus Edelhofer
Titus Edelhofer le 19 Avr 2012
Hi Daniel,
you are missing the initial condition: the integration of sin is -cos(x)+X0, where X0 is at first arbitrary.
But because the integration always starts at point zero:
int_0^0 sin(x) dx = 0
you get X0 = 1.
The curve you should see is not a sine but a -cosine shifted by one.
Titus
  2 commentaires
Daniel W
Daniel W le 19 Avr 2012
I see it now, makes sense. Thank you.
Kaustubha Govind
Kaustubha Govind le 19 Avr 2012
Daniel: Please accept Titus' answer since it has resolved your issue.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Simulink dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by