I'm trying to check for a NaN value in an array in if condition expression but the control is not entering inside if condition.

For example :

A = [1 2 3 NaN 3 5]; if isnan(A) ~= 0 %... end

Answer 1

[KSSV]

A = [1 2 3 NaN 3 5]; 

idx = isnan(A) ;  % all NaN indices at once 

for i = 1:length(A)

      if isnan(A(i))
          fprintf('%d index value is NaN\n',i)
      end
  end

[Bhargav Boddupalli]

Thank you. I was wondering if there is a way skipping use of 'for loop' to read each element.

[KSSV]

idx = isnan(A) ;  % all NaN indices at once 
A(~isnan(A))