sorting a matrix in descending order

I have a matrix

group =

     0     0     0     1
     0     1     0     0
     0     0     1     0
     0     1     0     0
     0     0     0     1
     0     0     1     0
     0     0     1     0
     0     1     0     0
     0     0     0     1
     0     1     0     0
     1     0     0     0
     0     1     0     0

if I want to sort in ascending order I can use

sortrows(group)

ans =

     0     0     0     1
     0     0     0     1
     0     0     0     1
     0     0     1     0
     0     0     1     0
     0     0     1     0
     0     1     0     0
     0     1     0     0
     0     1     0     0
     0     1     0     0
     0     1     0     0
     1     0     0     0

but I want to sort in descending order. What to do?

Answer 1

[the cyclist]

You can use a second input argument. By omitting it, you have effectively used

sortrows(group,[1 2 3 4])

for the ascending case. I believe what you want for the descending case is

sortrows(group,[-1 -2 -3 -4])

but you should verify that the result.

Answer 2

[bym]

sort(group,1,'descend')

[the cyclist]

I don't think this method retains the integrity of the rows, but rather sorts the columns independently.

[Asawari]

Can I use this descend command to arrange any array or matrix in descending order?I am using mesh command to create a curve.Mesh command creates origin of the curve between X-Y plane by default.I want to change the origin from X-Y plane to Y-Z plane and X axis I want to arrange in descending order,I am stuck here,can anyone help?

[the cyclist]

I suggest you make a new question, with more detail and maybe a small example. Questions buried in comments don't get seen as much.