Is there a function for finding the specific column number in a cell array?
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Helle everyone,
I think question is clear but, this is Matlab at all, I have a nx1 cell array and I want to know which column contains "WantedName" word. So firstly I have written a script to do this, but it takes so much time at debugging, because there are so many columns. I think there should be a function to do that like findcolumn(A, 'x'). my script that works fine for me;
names = fieldnames(EXC);
Snames = strfind(names, 'WantedName')
for k = 1:numel(Snames)
if Snames{k} == 1;
n = k
end
end
Fieldnames and 'WantedName'(s) are not corresponding word by word everytime, so I need to use strfind to find if 'WantedName' exists in a fieldname of EXC(struct). so strfind gives me cell array of names but place "1" for the column that have 'WantedName' in it. and then I need to do numel(names) times of for loop to find which column it is that having "1".
There should be a function to do that?? It is not the end of the world, script works well right now but I am curious.
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Walter Roberson
le 18 Oct 2017
[tf, idx] = ismember('WantedName', names);
Then, if tf is true then names{idx} is 'WantedName'.
You hint that you might have several wanted names. If so then
[tf, idx] = ismember(WantedNames, names);
where WantedNames is a cell array of strings to look for in names. tf(K) tells you if WantedNames{K} was found, and if it was found then idx(K) is the position in names.
3 commentaires
Burak Bayram
le 18 Oct 2017
Modifié(e) : Burak Bayram
le 18 Oct 2017
Walter Roberson
le 18 Oct 2017
If you have R2016b or later,
tf = startsWith(names, WantedNames)
This will return a logical array the same size as names (assuming it is a string array or cell array of character vectors) that tells you which of the entries start with something (anything) in Wantednames (which can be a character vector or string array or cell array of character vectors.)
Burak Bayram
le 18 Oct 2017
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