Error using sym/subsindex (line 796)

7 vues (au cours des 30 derniers jours)
Nate Mahorner
Nate Mahorner le 19 Oct 2017
Commenté : Star Strider le 19 Oct 2017
t1 = 588; %k
do = 3.5; % in
di = 3.0; % in
kp = 21.6; %W/(m*K)
ta = 294; % K
ts = 255.4; %k
h = 48.3; %W/(m^2*K)
deltar = 1; % in of calcium silicate insulation
e = .76;
at = pi*(do+2*deltar);
alm1 = (pi*(do-di))/(log(do/di));
alm2 = (2*pi*deltar)/log(do+2*deltar/do);
o = .0000000567; %W/(M^2*k^4)
d = .5; %do-di(in)
syms t2 t3 ki
eq1 = ki==.044+.0001144*(.5*(t2+t3)-283.333)
eq2 = 1/((d/(2*kp*alm1))+(deltar/ki*alm2))==(h*at(t3-ta)+e*o*at(t3^4-ts^4))/(t1-t3)
eq3 = (2*kp*alm1*(t1-t2))/((d)==h*at(t3-ta)+e*o*at(t3^4-ts^4))
[t2,t3,ki] = vpasolve([eq1,eq2,eq3],[t2,t3,ki],[0 inf;0 1])
t2 = double(t2)
t3 = double(t3)
ki = double(ki)
the error is in the eq2 line, eq1 seems to work fine.
  4 commentaires
Nate Mahorner
Nate Mahorner le 19 Oct 2017
@star strider I figured it out right before you answered! Thank you so much for the quick help!
Star Strider
Star Strider le 19 Oct 2017
The mystery nevertheless continues, since ‘s’ — either as a function or an array — appears nowhere in your code (that I can see).
Resolved it seems, regardless.

Connectez-vous pour commenter.

Réponse acceptée

Birdman
Birdman le 19 Oct 2017
You forgot to put an operator in front of your at variables in eq2 and eq3. Also, in the vpasolve function, choose your initial guess wisely. If you don't indicate an initial guess for your equations, MATLAB still finds answers. Hope this helps.
  1 commentaire
Nate Mahorner
Nate Mahorner le 19 Oct 2017
I figured it out right before you answered! Thank you so much for the quick help!

Connectez-vous pour commenter.

Plus de réponses (1)

Walter Roberson
Walter Roberson le 19 Oct 2017
You have at(t3-ta) and at(t3^4-ts^4) in that line, but at is not a function and and t3-ta and t3^4-ts^4 are not valid indices into the at variable

Catégories

En savoir plus sur Mathematics dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by