Any tips for bsxfun and repeated calculation?

4 vues (au cours des 30 derniers jours)
Marie
Marie le 29 Oct 2017
Commenté : Cedric le 30 Oct 2017
Hello,
I am currently using bsxfun to subtract the first column from matrix A from matrix A itself, which is straightforward. C=bsxfun(@minus,A,B); Say A= [1 2 3; 3 4 1; 1 5 7] and B = [1 3 1]'
I want to do the same for each column and separately stack up the output vertically one matrix after another. In this example, the resulting matrix would thus be:
D= [0 1 2; 0 1 -2; 0 4 6; -1 0 1; -1 0 -3; -4 0 2; -2 -1 0; 2 3 0; -6 -2 0]
Thanks in advance for any advice.

Réponse acceptée

Cedric
Cedric le 29 Oct 2017
Modifié(e) : Cedric le 29 Oct 2017
If you have MATLAB R2016b or above, BSXFUN was replaced by automatic expansion and you can do it as follows:
>> D = repmat( A, 3, 1 ) - A(:)
D =
0 1 2
0 1 -2
0 4 6
-1 0 1
-1 0 -3
-4 0 2
-2 -1 0
2 3 0
-6 -2 0
otherwise, almost the same as your first solution:
>> D = bsxfun( @minus, repmat( A, 3, 1 ), A(:) ) ;
Both are based on the fact that indexing A linearly will read it column first:
>> A(:)
ans =
1
3
1
2
4
5
3
1
7
  2 commentaires
Marie
Marie le 30 Oct 2017
Thank you for the clear reply; much appreciated!
Cedric
Cedric le 30 Oct 2017
My pleasure!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by