Hi everyone, Can you help me

If we list all the natural numbers up to 15 that are multiples of 3 or 5, we get 3, 5, 6, 9, 10, 12 and 15. The sum of these multiples is 60. Write a function called sum3and5muls that returns the sum of all the unique multiples of 3 or 5 up to n where n is a positive integer and the only input argument of the function. (Credit: Project Euler) I do anything the above question. I dont know loop yet. Can you give some hints please?

[Walter Roberson]

Please do not close questions that have an answer.

Answer 1

[Jos (10584)]

I give you a suggestion

tf = false(1,n)
tf(x:x:n) = true
w = find(tf)
sum(w)

Answer 2

[Walter Roberson]

Hint: 3:3:15

Answer 3

[Andrei Bobrov]

sum([3:3:n,5:5:n]);

[Walter Roberson]

This doesn't give use unique multiples.

Answer 4

[SULE SAHIN]

function sumof = sum3and5muls(n)
   sumof = sum([3:3:n])+sum([5:5:n])-sum([15:15:n]);

Problem 8 (sum3and5muls): Testing with argument(s) 1 Feedback: Your program made an error for argument(s) 1

    Your solution is _not_ correct.

What is wrong in my code?

[Andrei Bobrov]

Try

function sumof = sum3and5muls(n)
    sumof = sum([3:3:n,5:5:n]);
end

[Walter Roberson]

No, the problem talks about unique multiples.

[Walter Roberson]

SULE SAHIN: your code looks acceptable to me.