Better solution than mod() while indexing

5 vues (au cours des 30 derniers jours)
Luke Heyerdahl
Luke Heyerdahl le 3 Nov 2017
In this cutout, order is incremented each time through a loop, most likely more times than there are indexes in colors. Is there a better way to grab values in indexes in colors that avoids the if statement entirely?
ndx = (mod(order, length(colors));
if ndx = 0
ndx = length(colors);
end
color = colors(ndx));

Réponses (1)

Guillaume
Guillaume le 3 Nov 2017
Put the last colour first:
colors = [colors(end), colors(2:end-1)];
Then, simply mod and add 1:
color = colors(mod(ndx, numel(colors)) + 1);
If the loop just contains the code shown and the increment, then the loop can easily be eliminated. We would need to know how ndx is incremented though.

Catégories

En savoir plus sur Desktop dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by