Effacer les filtres
Effacer les filtres

how remove values which are out of ROI?

7 vues (au cours des 30 derniers jours)
Neda
Neda le 7 Nov 2017
Modifié(e) : Neda le 7 Nov 2017
I'm trying remove these red values on the vertical lines of attached image, and those on black region? I would really appreciate any idea. I tried the following code, but I'm getting an error which saying Warning: Polynomial is not unique; degree >= number of data points.
now it removed some of the values, but I think the way I'm doing isn't efficient or I'm doing something wrong. the image before remove those values is attached as well.
function display_skew_final2(ST, Im,Frame)
close all;
load Im
Contrast_maxi = max(Frame(1:1).Contrast(:));
colors = {'r'};
figure; imshow (Im(:,:,1));
for idxcol = 1:size(ST.KernelX,1)
for idxrow = 1:size(ST.KernelY,1)
Contrast= Frame(1:1).Contrast(idxrow,idxcol);
Skew= Frame(1:1).Skew(idxrow,idxcol);
Normalize_Contrast = Contrast/Contrast_maxi ;
radi_Contrast(:) = Normalize_Contrast;
Skew_radi(:) = Skew;
Skew_values= Frame(1:1).Skew;
for ROWCircleCenter = ST.KernelY(idxrow);
for COLCircleCenter = ST.KernelX(idxcol);
centers = [COLCircleCenter ROWCircleCenter];
coefs = polyfit( ROWCircleCenter, COLCircleCenter,1);
slope = coefs(1);
T = table(ROWCircleCenter,COLCircleCenter,slope,'VariableNames',{'X','Y','slope'})
if (Skew_radi < 0)
Skew_radi2 = abs(Skew_radi); else Skew_radi2 = Skew_radi; end
if (radi_Contrast > 0.18)
if slope >2; Skew_radi2 = 0; end
axis ij
viscircles (centers,Skew_radi2,'Color',colors{1});
% rectangle('Position',[(COLCircleCenter) (ROWCircleCenter) Skew_radi2 Skew_radi2],'Curvature',[1 1],'FaceColor',[1 0 0],'EdgeColor',[1 0 0],'LineWidth',5)
end
end
end
end
end
end

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