- What is the purpose of the loop in your code? Note that at each iteration, you're completely overwriting the previous value of c, d and e.
- Is a loop required to do what you want? (Hint: No)
- How can you have a different equation for the last term? (Hint: calculate all the other terms from 1 to n-1 instead of up to n)
- What happens with your code if the user enters a column vector instead of a row vector? (Hint: use numel instead of size(x, 2))
Setting up vector function
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I write a function SetUp to set up three vectors from an input vector k. Vector c = (-k(2); -k(3); ..... -k(n)) where I have n-1 elements. Vector d = (k(1)+k(2); k(2)+k(3); ...... k(n-1)+k(n); k(n)) where there are n elements And vector e = vector c.
Here is the code I wrote:
function [c,e,d] = SetUp
k = input('Enter k vector');
n = size(k,2);
for k1 = 1:n
c = -k(k1)*ones(n-1,1);
d = (k(k1)+k(k1+1))*ones(n,1); d(n) = k(n);
e = c;
end
end
By running this code I get an error: Index exceeds matrix dimensions.
Problem is in this line: d = (k(k1)+k(k1+1))*ones(n,1); d(n) = k(n);
In my opinion the problem is in indexing as the last term when Matlab runs d = (k(k1)+k(k1+1))*ones(n,1); is d = k(n)+k(n+1), where the program does not recognize k(n+1) as there is no such term in vector k.
So, the question is, how to overcome this problem as I don't even need the last term as the last term is d(n) = k(n)???
Thanks in advance!
1 commentaire
Guillaume
le 9 Nov 2017
You have to ask yourself several questions:
Réponse acceptée
Eric
le 9 Nov 2017
Modifié(e) : Eric
le 9 Nov 2017
In your for loop, you are using k(k1+1). if k1 is the last element of k, then k(k1+1) will be exceeding the dimension of k. If you dont care about the last term, use
for k1 = 1:n-1
... Stuff ...
end
d(n) = k(n);
or if you need the other vectors to go to n, stick it in a conditional
for k1 = 1:n
... Other Stuff ...
if k1~=n
d = (k(k1)+k(k1+1))*ones(n,1);
end
end
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!