how can i segment characters from the image with lot of white pixels and similar background like text ?

1 vue (au cours des 30 derniers jours)
i need to segment the character part of image and then each individual characters as a seperate image. i am having problem to do in matlab. Here is the image attached. P.S. : I have tried earlier answers for character segmentation, but this image seems a bit difficult. could anybody please help :)
i want to segment the portion containing characters into a seperate image. so my aim is not to just recognize text but to segment it as an image from above image. Finally i want to compare the segmented image of hello world from this printed board with the reference image which is made in paint and have just hello world witten in it. So main aim is Kinda quality comparison of printed image with 100 percent accurate image, so basically how good each character it is printing.
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Avinash Kumar
Avinash Kumar le 10 Nov 2017
Modifié(e) : Avinash Kumar le 10 Nov 2017
yes, ocr doesnt seem to work. As background is quite similar to the text here. this is what ocr return instead of hello world : ocrText with properties:
Text: 'efloflwofldi↵↵'
CharacterBoundingBoxes: [11×4 double]
CharacterConfidences: [11×1 single]
Words: {'efloflwofldi'}
WordBoundingBoxes: [47 2 302 55]
WordConfidences: 0.1218
Moreover i want the segmented result as image as i want to kinda compare quality of printing on this board with original reference image of hello world.

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Image Analyst
Image Analyst le 10 Nov 2017
You just need to subtract the images:
diffImage = abs(double(grayImage) - double(refImage));
Then see if you have a significant number of pixels above zero. If you do, then the test image does not say Hello World.
  16 commentaires
Image Analyst
Image Analyst le 15 Nov 2017
bwareafilt() will not introduce any additional blobs, like those in the corner. You can delete blobs touching the border with imclearborder().
Avinash Kumar
Avinash Kumar le 15 Nov 2017
yes, this works :D Thanks a lot for all your help. If i have any question again, i will open this thread.

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