Info
Cette question est clôturée. Rouvrir pour modifier ou répondre.
Running if loop until a specific outcome
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have two double vectors, a and b. Both have values for each time point t. I want to run a loop where
- -for each time t,
- --if a >= 0.5 and the next value that is >=0.5 is in a, outa = outa + 1
- --if a >= 0.5 and the next value that is >=0.5 is in b, outc = outc + 1
- --if b >= 0.5 and the next value that is >=0.5 is in b, outb = outb + 1
- --if b >= 0.5 and the next value that is >=0.5 is in b, outc = outc + 1
How might I be able to do this?
3 commentaires
Réponses (1)
Image Analyst
le 20 Nov 2017
Evidently i and k are different lengths, so that when ix goes from 2 to max(length(i),length(k)), it will be too long for the shorter of those two vectors. Before the loop put this:
length(i)
length(k)
max(length(i),length(k))
Then tell me what is is when it throws the error (look in the workspace panel).
3 commentaires
Image Analyst
le 20 Nov 2017
OK, so at some point, since ix runs from 2 to 219533, ix will take on the value of 48681 (one longer than i is). So when it does this
if i(ix) < k(ix) && i(ix+1) < k(ix)
which means
if i(48680) < k(48680) && i(48680+1) < k(48680)
Now i(48680+1) is i(48681). And since there is no 48681st element of (the badly named) i, it will thrown an error.
Cette question est clôturée.
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!