arrenging rows and columns ?

suppose i have latitude

-90
-60 
-30 
00 
30 
60
90

and longitude

 -160 -120 -80 -40 00 40 80 120 160

i want output as

 -90 -160
 -60 -160
-30 -160
00 -160
30 -160
60 -160
90 -160
-90 -120
-60 -120
-30 -120
00 -120
30 -120
 60 -120 
 90 -120
.
.
.

like that for all points. Any idea how could i do that ?

Answer 1

[Jan]

lat   = [-90 -60 -30 00 30 60 90]';
long  = [ -160 -120 -80 -40 00 40 80 120 160 ];
nLat  = length(lat);
nLong = length(long);
both  = [repmat(lat, nLong, 1), repelem(long(:), nLat, 1)];

Alternatively for old Matlab versions, which do not have repelem:

tmp  = repmat(long, nLat, 1);
both = [repmat(lat, nLong, 1), tmp(:)];

Answer 2

[Andrei Bobrov]

lat   = [-90 -60 -30 00 30 60 90]';
long  = [ -160 -120 -80 -40 00 40 80 120 160 ];

[x,y] = ndgrid(lat,long);
out = [x(:),y(:)];

Answer 3

[Birdman]

a=[-90 -60 -30 00 30 60 90];
b=[-160 -120 -80 -40 00 40 80 120 160];
a=a(:);b=b(:);
aa=repmat(a,length(b),1);
bb=repmat(b,length(a),1);
c=[aa bb]

[pruth]

thank you for your reply

it is giving me an error

Error using horzcat Dimensions of matrices being concatenated are not consistent.

[Birdman]

this one works.

[Jan]

@cvklpstunc: It works, but does not give the correct result: The 2nd column contains [-160; -120; -80; ...; 120; 160; -160; -120; ...] instead of the wanted [-160; -160; -160; ...]. It works, if you omit "b=b(:)" and reshape it after the repmat:

a  = a(:);
aa = repmat(a,length(b),1);
bb = repmat(b,length(a),1);
c  = [aa, bb(:)]