why won't this code run?

7 vues (au cours des 30 derniers jours)
LM
LM le 23 Nov 2017
Commenté : LM le 23 Nov 2017
[find(stock.permno)]==notrading(1);
for i=1:18522
end
for j=10137
newt=[find(toremove(i)==c)],:)=[];
end
for i=0:4
t((1+(i*126)):(126+(i*126)),:)=c((253+(i*378)):(379+(i*378)),:);
end
for i=1:5
trade(i).permno=top5(i,1);
for ii=0:4
trade(ii+1).price=d(1+(ii*252):252+(ii*252),4);
end
  1 commentaire
KSSV
KSSV le 23 Nov 2017
How did you run? What error you got?

Connectez-vous pour commenter.

Réponse acceptée

Bshara Murr
Bshara Murr le 23 Nov 2017
Modifié(e) : Bshara Murr le 23 Nov 2017
Probably because you used the same local variable inside the main and nested loop. Try replacing the second i by a j (in every instance you are referring to it), and end your "for" loops.

Plus de réponses (1)

Walter Roberson
Walter Roberson le 23 Nov 2017
You have
newt=[find(toremove(i)==c)],:)=[];
which attempts to do two assignments in one statement.
  3 commentaires
Walter Roberson
Walter Roberson le 23 Nov 2017
Possibly you want
newt(find(toremove(i)==c),:)=[];
but it is difficult to be sure as your code does not mention newt anywhere else.
LM
LM le 23 Nov 2017
got another error once i fixed it saying find has too many input arguments

Connectez-vous pour commenter.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by