for loops for two variables (not nested loop)

3 vues (au cours des 30 derniers jours)
UET Hussain
UET Hussain le 30 Nov 2017
Modifié(e) : UET Hussain le 18 Jan 2018
I've a .dat file with 73280 length. i'm trying to find mean of first 100 values, then mean of 101 to 200 values, then 201 to 300 and so on until last 100 values. 1st error i got was "Index exceeds matrix dimensions." I rounded off the length to 73200 and got rid of this problem.
x = [];
y = rms (a1,100); %a1 is original data
b= length(y);
c= b/100;
for i =1:100:b
x= [mean(y(i:i+99))]
end
subplot (2,2,1); plot (t1, a1)
subplot (2,2,2); plot (x)
subplot (2,2,3); plot (t1,y)
the value of "x" is updating in every iteration. what i want is to store the every value of "x" and then plot it.
  1 commentaire
UET Hussain
UET Hussain le 30 Nov 2017
Modifié(e) : Stephen23 le 30 Nov 2017
when I try to apply another for loop,
x = [];
y = rms (a1, 100);
b= length(y);
c= b/100;
for i =1:100:b, j=1:c;
x= [mean(y(i:i+99))]
end
subplot (2,2,1); plot (t1, a1)
subplot (2,2,2); plot (x)
subplot (2,2,3); plot (t1,y)
it actually becomes nested loop, which i dont want

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Réponse acceptée

Stephen23
Stephen23 le 30 Nov 2017
A loop is not required. Just use reshape. Then you can plot them all at one too!
>> N = 100;
>> V = rand(1,73280); % your data vector
>> Z = N*fix(numel(V)/N);
>> M = mean(reshape(V(1:Z),N,[]),1);
>> plot(M)
  1 commentaire
UET Hussain
UET Hussain le 30 Nov 2017
Modifié(e) : UET Hussain le 18 Jan 2018
Hi Stephen...... thanks for reply... what if i dont know the size of a file (n above case "73280")????? actually i have over over 225 files hence cannot look at each file everytime i'm going to process it.

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Plus de réponses (1)

M
M le 30 Nov 2017
You can use
x=[x mean(y(i:i+99))];
  1 commentaire
UET Hussain
UET Hussain le 30 Nov 2017
i'm using the same thing, Sir.... but cant get the desired result

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