Dear all,
I have written a code for linspace I want a 3D plot of it:
% First we set the constants:
kd=6;
lambda= 0.01;
Delta_E=0.02;
% Then we write down the Formulas:
z=linspace(-1,1,200);
kappa=linspace(0,1,200);
q=((Delta_E)+(lambda.*z)+(((sqrt((1+z)./2)).*exp(-(kd.*(sqrt(2.*lambda'.*(1+z))))))).*(kappa.*(sqrt((1-z)./(1+z)))-(sqrt((1+z)./(1-z )))));
% Now we plot q(Z,kappa) vs Z and kappa :
figure(1)
mesh(z,kappa,q)
% title('kd=6');
xlabel('Z');
ylabel('lambda');
zlabel('q)');
I think that my "q" must have 200*200 matrix, but it is not. Its gives just 1*200.
I would highly appreciate if you help me.
Thanks,

 Réponse acceptée

Walter Roberson
Walter Roberson le 30 Nov 2017
Change
z=linspace(-1,1,200);
kappa=linspace(0,1,200);
to
Z = linspace(-1,1,200);
KAPPA = linspace(0,1,200);
[z, kappa] = meshgrid(Z, KAPPA);
Note: you have
ylabel('lambda');
which is not correct. Your lambda is a constant. Your y axes is kappa, not lambda.

2 commentaires

fartash2020
fartash2020 le 30 Nov 2017
Modifié(e) : Walter Roberson le 30 Nov 2017
Dear Walter,
Thank you very much for your answer. Also, I want to plot Z vs kappa for the time that q=0. in 2D of course.
Best Regards,
contour(z, kappa, q, [0 0])
the [0 0] is a trick that has to be used when you are only asking for one contour value; if you were to try to pass in the scalar 0 at that point, it would try to interpret the scalar 0 as the number of contour levels to draw.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Line Plots dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by