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Get node names after a graph condensation

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stam dadi
stam dadi le 4 Déc 2017
Commenté : Waseem AL Aqqad le 27 Nov 2021
I have an adjacency matrix adj and a cellarray nodeManes that contains names that will be given to the graph G that will be constructed from adj
So I use
G = digraph(adj,nodeNames);
And I get the following graph :
Now , I want to find the strongly connected components in G and do a graph condensation so I use the following :
C = condensation(G);
p2 = plot(C);
So I get the following graph :
So I have 6 strongly connected components , but my problem is that I lost the node names , I want to get something like :
Is that any way to get the nodes names in the result of the condentation ?
Thanks.

Réponse acceptée

Christine Tobler
Christine Tobler le 4 Déc 2017
Here is some code that does this:
bins = conncomp(G);
compNames = cell(max(bins), 1);
for ii=1:length(bins)
if isempty(compNames{bins(ii)})
compNames{bins(ii)} = G.Nodes.Name{ii};
else
compNames{bins(ii)} = [compNames{bins(ii)} ', ' G.Nodes.Name{ii}];
end
end
C.Nodes.Name = compNames;
plot(C);
There's no one-line command to combine several node names based on the vector of bins used in condensation, so I wrote a for-loop to do this instead.
  2 commentaires
stam dadi
stam dadi le 4 Déc 2017
Thank's
Waseem AL Aqqad
Waseem AL Aqqad le 27 Nov 2021
Thanks, Christine

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 4 Déc 2017
Stealing basic technique from Christine, and reworking it without a loop:
bins = conncomp(G);
temp = accumarray(bins.', (1:length(bins)).', [], @(IDX) {G.Nodes.Name(IDX)});
C.Nodes.Name = cellfun(@(CS) strjoin(CS, ', '), temp, 'uniform', 0);
  10 commentaires
stam dadi
stam dadi le 5 Déc 2017
yes.. I just checked , I accidently deleted the line :
C = condensation(G);
Thank's
Waseem AL Aqqad
Waseem AL Aqqad le 27 Nov 2021
Wow! Thanks.

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