How to make it a one line code?
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matrix= [1 0 -1 0.001 4; 5.9 -1 3.15 1 1.11 ] ;
cell_conv = (num2cell(matrix));
find_one = abs( matrix ) == 1 ;
cell_conv(find_one)={'hey'}
2 commentaires
KSSV
le 6 Déc 2017
You can striagh away use:
cell_conv(abs( matrix ) == 1)={'hey'}
oshawcole
le 6 Déc 2017
Modifié(e) : Walter Roberson
le 15 Oct 2023
Réponse acceptée
Plus de réponses (1)
Jos (10584)
le 6 Déc 2017
Here is another but shorter two-liner using a functional programming approach for anonymous function:
matrix= [1 0 -1 0.001 4; 5.9 -1 3.15 1 1.11 ]
iif = @(varargin) varargin{2 * find([varargin{1:2:end}], 1, 'first')}() ;
% functional programming of a "if ... elseif ... else" construction
out = arrayfun(@(X) iif(isequal(abs(X),1), @() 'hey', true, @() X), matrix, 'un', 0)
3 commentaires
Walter Roberson
le 6 Déc 2017
Modifié(e) : Walter Roberson
le 15 Oct 2023
I think that may be the first usable iif that I have seen in MATLAB. (I remember someone posting one a few years ago but I had my doubts about whether it would work.)
Jos (10584)
le 7 Déc 2017
Credits should go to Loren Shure
Walter Roberson
le 8 Déc 2017
Ah, I remember now why I had forgotten Loren's solution: it was because I cannot think of any way of tricking MATLAB to return something for commands that return no output. For example if one of the branches was
@(x) set(handles.push7, 'Value', x)
and the other branch was
@(x) fprintf('hey')
then the fprintf() officially returns the number of bytes emitted so it can be used in arrayfun, but the set() has no output and cannot be used, not even when 'uniform', 0 is used.
I suppose I could write a real function
function yelm = empty(function_handle);
function_handle();
yelm = [];
end
and then code with
@(x) empty( @() set(handles.push7, 'Value', x) )
But I dislike having to write true functions to implement functional programming.
I know in HG2 that I could write
handles.push7.Value = x
and that returns handles.push7, but assignment in functional programming is ugly in MATLAB... though you can get this particular one to work:
newval = arrayfun(@(x) subsasgn(handles.push7, struct('type','.','subs','Value'), x),randi(7,1,5))
The output variable is mandatory in this situation.
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