Loop for bvp4c function with an unknown parameter

20 vues (au cours des 30 derniers jours)
Ramin Rabani
Ramin Rabani le 7 Déc 2017
Modifié(e) : MINATI le 24 Mai 2020
I tried to solve sixth order differential equation using bvp4c with an unknown parameter “S” and one variable parameter “k”. I have written a subroutine as a bvp4c and a main function for “k”.
The main code is written as follows:
function [] = main()
kk=0.5 ;
for i=1:60
k=kk;
valuePresentstudy = Surfactant(k);
kk=kk+0.1;
end
end
The bvp4c subroutine is written as follows:
function valuePresentstudy = Surfactant(k)
options = bvpset('NMax',100000);
S=0.28;
solinit = bvpinit(linspace(0,1,100),[0.1 0 0 0 0 0],S);
sol = bvp4c(@(x,y)fourode(x,y,k),@(ya,yb)fourbc(ya,yb,k),solinit,options);
save hatimsol.mat sol
x = linspace(0,1);
y = deval(sol,x);
valuePresentstudy=y;
%
function dydx = fourode(x,y,S,k)
Pr=10;
dydx = [ y(2); y(3); y(4); -(k^4+(S/Pr)*k^2)*y(1)+(2*(k^2)+(S/Pr))*y(3); y(6); (k^2+S)*y(5)-y(1)];
%
function res = fourbc(ya,yb,S,k)
e=0;
res = [ ya(1); ya(2); ya(5); yb(1); yb(6)+e*k*yb(5); yb(5)-1; yb(6)];
The error is given as:
Error using Surfactant>@(x,y)fourode(x,y,k)
Too many input arguments.
Error in bvparguments (line 105)
testODE = ode(x1,y1,odeExtras{:});
Error in bvp4c (line 130)
bvparguments(solver_name,ode,bc,solinit,options,varargin);
Error in Surfactant (line 5)
sol = bvp4c(@(x,y)fourode(x,y,k),@(ya,yb)fourbc(ya,yb,k),solinit,options);
Error in MainPresentSurfactant (line 6)
valuePresentstudy = Surfactant(k);
Could you please tell me where my mistake is?
Thanks in advance for your help.

Réponse acceptée

Torsten
Torsten le 7 Déc 2017
Maybe
sol = bvp4c(@(x,y,S)fourode(x,y,S,k),@(ya,yb,S)fourbc(ya,yb,S,k),solinit,options);
Otherwise pass k to fourode and fourbc as global.
Best wishes
Torsten.
  1 commentaire
Ramin Rabani
Ramin Rabani le 7 Déc 2017
Modifié(e) : Ramin Rabani le 7 Déc 2017
Thank you for your reply. it Worked for me. Thanks a lot for your help

Connectez-vous pour commenter.

Plus de réponses (2)

Torsten
Torsten le 7 Déc 2017
function [] = main()
kk=0.5 ;
for i=1:60
k=kk;
valuePresentstudy = Surfactant(k);
kk=kk+0.1;
end
end
function valuePresentstudy = Surfactant(k)
global kk
kk = k;
options = bvpset('NMax',100000);
S=0.28;
solinit = bvpinit(linspace(0,1,100),[0.1 0 0 0 0 0],S);
sol = bvp4c(@fourode,@fourbc,solinit,options);
save hatimsol.mat sol
x = linspace(0,1);
y = deval(sol,x);
valuePresentstudy=y;
%
function dydx = fourode(x,y,S)
global kk
Pr=10;
dydx = [ y(2); y(3); y(4); -(kk^4+(S/Pr)*kk^2)*y(1)+(2*(kk^2)+(S/Pr))*y(3); y(6); (kk^2+S)*y(5)-y(1)];
%
function res = fourbc(ya,yb,S)
global kk
e=0;
res = [ ya(1); ya(2); ya(5); yb(1); yb(6)+e*kk*yb(5); yb(5)-1; yb(6)];
Best wishes
Torsten.
  1 commentaire
Tanya Sharma
Tanya Sharma le 7 Oct 2019
Hi Torsten, I am working on a similar kind of problem where S is unknown eigenvalue.
Can I evaluate eigenvalues S using bvp4c?

Connectez-vous pour commenter.


Akmaral Pussurmanova
Akmaral Pussurmanova le 6 Mai 2020
I don't know where is a mistake( Can you help me?
function dxdt = mat4ode(t,x,mu) % equation being solved
alfa = 0;
dxdt = [x(2)
-x(1)+0.1*(alfa*cos(2*t)*x(1)+x(1)^3)+mu*sin(2*t)+(1-pi^2)*sin(pi*t)+1-0.1*((sin(pi*t)+1)^3)-2*sin(2*t)];
end
%-------------------------------------------
function res = mat4bc(xa,xb,mu) % boundary conditions
res = [xa(1)-1
xb(1)-1
xa(2)-xb(2)];
end
%-------------------------------------------
function yinit = mat4init(t) % initial guess function
yinit = [sin(pi*t)+1
pi*cos(pi*t)
];
end
mu=2;
solinit = bvpinit(linspace(0,2,20),@mat4init,mu);
sol = bvp4c(@mat4ode, @mat4bc, solinit);
fprintf('Fourth eigenvalue is approximately %7.3f.\n',...
sol.parameters)
xint = linspace(0,2);
Sxint = deval(sol,xint);
plot(xint,Sxint)
axis([0 2 -4 4])
title('Eigenfunction of Mathieu''s Equation.')
xlabel('x')
ylabel('y')
legend('y','y''')
  1 commentaire
MINATI
MINATI le 24 Mai 2020
Modifié(e) : MINATI le 24 Mai 2020
Dear
Akmaral
Post ur doubt in another question page and mail me the link @
minatipatra456@gmail.com

Connectez-vous pour commenter.

Tags

Aucun tag saisi pour le moment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by