Extracting numbers from cell using regex

Hi,
I have the following cell:
C = {'2/6';'78/6';'982/47';'11/6'}
I would like to extract all numbers from before / and place them in a new matrix, and all numbers from after / and place them in another matrix.
The result should be something like this:
A=[2;78;982;11] B=[6;6;47;6]
How can i do this? I guess using regex would be the easiest way, but how to write it so it extracts it as explained?
Thank you for your help.

Réponses (2)

Walter Roberson
Walter Roberson le 10 Déc 2017
C = {'2/6';'78/6';'982/47';'11/6'};
One way:
temp = cell2mat(cellfun(@str2double,regexp(C, '(\d+)/(\d+)', 'tokens','once'),'uniform',0));
A = temp(:,1);
B = temp(:,2);
Another way:
temp = cell2mat(regexp(C, '(?<A>\d+)/(?<B>\d+)', 'names'));
A = str2double({temp.A}.');
B = str2double({temp.B}.');
Another way:
temp = cell2mat(cellfun(@str2double,regexp(C,'/','split'),'uniform',0));
A = temp(:,1);
B = temp(:,2);
Another way:
A = str2double(regexp(C,'\d+(?=/)','match','once'));
B = str2double(regexp(C,'(?<=/)\d+','match','once'));
Jos (10584)
Jos (10584) le 10 Déc 2017
You can use cellfun to scan every string:
C = {'2/6';'78/6';'982/47';'11/6'}
V = cellfun(@(c) sscanf(c,'%f/%f'), C, 'un', 0) ;
AB = cat(2,V{:})
A = AB(1,:)
B = AB(2,:)

5 commentaires

kalili
kalili le 10 Déc 2017
I am sorry, I was a bit wrong when writing the question. The data is of type cell, not string: C = {2/6;78/6;982/47;11/6}
Jos and I have assumed your C was what you posted before, a cell array of character vectors. Our answers work with the C you had posted earlier. But if your C is a cell array of numeric values:
>> C = {2/6;78/6;982/47;11/6}
C =
4×1 cell array
{[0.333333333333333]}
{[ 13]}
{[ 20.8936170212766]}
{[ 1.83333333333333]}
then it is not possible to recover the original numerators and denominators: you can just get approximations of the reduced fractions:
[A,B] = rat(cell2mat(C))
Jos (10584)
Jos (10584) le 10 Déc 2017
@kalili ... sigh ...
Well, how did you get, for instance, the 2 and the 6 in cell 1 in the first place? Maybe you can skip that step?
kalili
kalili le 12 Déc 2017
Hm, the data was obtained by importing an excel sheet using [~,~,C]=xlsread(filename).
What shows up for
class(C{1})
When you use the third output of xlsread(), then anything that looks like a plain number will be converted to numeric but anything else will be left alone. Approximately speaking, it is like
temp = read cells as text
temp_numeric = str2double(temp);
mask = ~isnan(temp_numeric);
temp(mask) = num2cell(temp_numeric(mask))
so '2/6' should have been left alone as text because str2double() if it would be nan. Note that str2num() is not used for this purpose: str2num() would evaluate the text as an expression, getting the 0.333<etc> but that is not going to be used.

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