Working with dde23 for a simple problem

I'm trying to solve this: xdot = -Lx(t-1) where x is a 3x1 vector and L a constant 3x3 matrix. The initial conditions for x are [0 0 0]'for t<0. For some reasons, I'm having trouble with framing the DDE.I have seen the comprehensive manual already. Yours inputs are appreciated. Thanks.

[Torsten]

Solution is x=[0 0 0] for all t.

Best wishes

Torsten.

[Deepayan Bhadra]

I'm afraid that doesn't seem to be correct.

[Torsten]

Why ?

[Deepayan Bhadra]

With non-zero initial conditions, can it be solved to give a proper output?

Answer 1

[Jan]

If x is [0;0;0] for t < 0 and xdot = -L * x(t-1), you get xdot=[0;0;0] for the time 0<=t<=1. If you integrate this, x will remain [0;0;0] and this argument can be expanded to the following intervals also.

[Deepayan Bhadra]

With non-zero initial conditions, can it be solved to give a proper output?

[Jan]

Yes. But you are asking for [0;0;0] explicitly.

Did you read https://www.mathworks.com/matlabcentral/fileexchange/3899-tutorial-on-solving-ddes-with-dde23 already? Maybe it would be helpful if you explain, which problem you have. "For some reasons, I'm having trouble with framing the DDE" does not reveal, which troubles you are faced with.