Index exceeds matrix dimensions det
Afficher commentaires plus anciens
D is matrix right? why det(D) not work someone help me
Réponses (2)
Ahmos Sansom
le 14 Déc 2017
0 votes
Check the condition cond(A) or try 1/det(A):
Read:
You have provided very few information, such that the readers have to guess. My idea:
You have defined "det" as a variable before:
X = randi([1, 100], [3, 3]);
det(X);
...
det = ones(2, 2);
det(X) % Indices out of range
Check this by typing into the command window:
dbstop if error
Then run the code again and when it stops, check what "det" is:
which det -all
If this is the problem, the solution is easy: Do not shadow built-in functions by local variables.
Catégories
En savoir plus sur Linear Algebra dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!