how to sort in increasing order using loop?

for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

6 commentaires

David Goodmanson
David Goodmanson le 16 Déc 2017
Hello baiti, what don't you like about this? It's a bubble sort in increasing order and it works.
baiti
baiti le 16 Déc 2017
then, i think my matlab is the problem. i really dont have any idea why it wont work on my matlab. any suggestion?
David Goodmanson
David Goodmanson le 16 Déc 2017
It's cleaner to put A = zeros(1,6) at the beginning, so that if you run the script more than once you get a fresh start for A. I put disp(A) at the end as well, so that you can see the results of your efforts.
Image Analyst
Image Analyst le 16 Déc 2017
To format your code read this
Why don't you just use the built-in sort() function?
Jan
Jan le 17 Déc 2017
@baiti: It seems like you have a problem running this code. Then it would be useful, if you mention what the problem is. "it wont work on my matlab" does not allow to reconsider, why you are not satisfied.
Manish Kumar
Manish Kumar le 26 Juin 2020
Do you want better algorithm than this?

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Réponses (1)

rohan hazarika
rohan hazarika le 18 Sep 2020
for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

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